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HRID605234

反应详情

EQUATION

反应方程式

HRID 605234 的结构方程式

REACTANTS

反应物

2
结构：Nc1ccc(F)cn1
HCID2737701

5-Fluoropyridin-2(1H)-imine

C5H5FN2

结构：O=C(Cl)c1ccc(F)c([N+](=O)[O-])c1
HCID2783347

4-fluoro-3-nitrobenzoyl chloride

C7H3ClFNO3

PRODUCTS

生成物

1
结构：O=C(Nc1ccc(F)cn1)c1ccc(F)c([N+](=O)[O-])c1
HCID63236206

未命名化合物

收率 98%

PROCEDURE

实验过程

The product from Example 172a was reacted with 5-Fluoro-pyridin-2-ylamine (165 mg, 1.474 mmol) according to the procedure from Example 172a to provide the title compound (404 mg, 98%).