HRID60640

反应详情

EQUATION

反应方程式

HRID 60640 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

A solution of Intermediate G (153 mg, 0.28 mmol) and [5-tert-butyl-2-(3-chloro-4-triisopropylsilanyloxy-phenyl)-2H-pyrazol-3-yl]-carbamic acid 2,2,2-trichloro-ethyl ester (WO2011/154734A1, which is incorporated herein by reference, 167 mg, 0.28 mmol) in 1,4-dioxane (4 mL) and DIPEA (87 μL, 0.50 mmol) was stirred at 95° C. for 4 h. The cooled mixture was concentrated in vacuo. The residue was purified by FCC, using 0-7.5% MeOH in DCM, to give 1-[5-tert-butyl-2-(3-chloro-4-triisopropylsilanyloxy-phenyl)-2H-pyrazol-3-yl]-3-{(1S,4R)-4-[3-(4-triisopropylsilanyloxymethyl-piperidin-1-yl)-[1,2,4]triazolo[4,3-a]pyridin-6-yloxy]-1,2,3,4-tetrahydro-naphthalen-1-yl}-urea (193 mg). This was dissolved in THF (3 mL) and treated with TBAF (1M in THF, 0.47 mL, 0.47 mmol). The solution was stirred at RT for 1.75 h, then diluted with water and extracted with DCM (3×20 mL). The combined organics were dried and concentrated in vacuo. The residue was purified by FCC, using 0-25% [2M NH3 in MeOH] in DCM, to give the product. This was further purified by HPLC (C18 X-select column, 30-98% MeCN in H2O, 0.1% HCO2H) to give the title compound (72 mg, 56%). LCMS (Method 5): Rt 3.99 min, m/z 685 [MH+]. 1H NMR (400 MHz, d6-DMSO): 1.26 (9H, s), 1.38-1.52 (2H, m), 1.55-1.66 (11H, m), 1.73-1.96 (4H, m), 1.98-2.17 (2H, m), 2.85-2.97 (2H, m), 3.3-3.5 (4H, m, under water signal), 4.52 (1H, br s), 4.77-4.85 (1H, m), 5.55 (1H, br t, J=4.4 Hz), 6.28 (1H, s), 7.05 (1H, s), 7.08 (1H, s), 7.15 (1H, dd, J=2.0, 9.8 Hz), 7.23-7.40 (5H, m), 7.44 (1H, d, J=2.5 Hz), 7.61 (1H, d, J=9.9 Hz), 7.64 (1H, br d, J=1.5 Hz), 8.02 (1H, br s), 10.55 (1H, br s).

WORKUP

后处理

  1. concentrationThe cooled mixture was concentrated in vacuo
  2. customThe residue was purified by FCC