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HRID6066

反应详情

EQUATION

反应方程式

HRID 6066 的结构方程式

REACTANTS

反应物

2
结构：C=CCCC(C[C@@H]1OC(=O)[C@H]1CCCCCC)OC(=O)[C@H](CC(C)C)NC=O
HCID86743995

未命名化合物

结构：[H][H]
HCID178418361

未命名化合物

PRODUCTS

生成物

1
结构：CCCCCC[C@@H]1C(=O)O[C@H]1CC(CCCC)OC(=O)[C@H](CC(C)C)NC=O
HCID86743994

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

2
结构：[Pd]
催化剂HCID23938

Palladium

Pd

结构：C1CCOC1
溶剂HCID8028

Tetrahydrofuran

C4H8O

PROCEDURE

实验过程

A solution of 10 mg of N-formyl-L-leucine 1-[(trans-3-hexyl-4-oxo-2-oxetanyl)methyl]-4-pentenyl ester in 0.5 ml of THF was treated with 2.5 mg of 5% Pd/C and hydrogenated. After the hydrogen uptake was finished the catalyst was filtered off and the filtrate was evaporated in vacuo. The residue was chromatographed over silica gel with toluene/ethyl acetate (8:2) and there was obtained amorphous N-formyl-L-leucine 1-[(trans-3-hexyl-4-oxo-2-oxetanyl]-methyl]pentyl ester as a mixture of 2 diastereomers.

WORKUP

后处理

  1. filtrationwas filtered off
  2. customthe filtrate was evaporated in vacuo
  3. customThe residue was chromatographed over silica gel with toluene/ethyl acetate (8:2)