3-Iodophenol → 5-(3-Hydroxyphenylethynyl)-nicotinonitrile
Reaction equation
I[C:2]1[CH:3]=[C:4]([OH:8])[CH:5]=[CH:6][CH:7]=1.[C:9]([C:11]1[CH:12]=[N:13][CH:14]=[C:15]([CH:18]=1)[C:16]#[N:17])#[CH:10]>>[OH:8][C:4]1[CH:3]=[C:2]([C:10]#[C:9][C:11]2[CH:12]=[N:13][CH:14]=[C:15]([CH:18]=2)[C:16]#[N:17])[CH:7]=[CH:6][CH:5]=1Participants
3
Procedure
Prepare essentially as described in EXAMPLE 10 using 3-iodophenol (0.69 g, 3.0 mmol) and 5-ethynylnicotinonitrile (0.4 g, 3.0 mmol) to give the title compound (110 mg, 17%).
Workup
- customPrepare essentially
Sources & evidence
- ORD record
- ord-0aa0978605eb4a59b7d0246e7861106d
- Source dataset
- uspto-grants-2011_03
- Patent number
- US07915424B2
Reaction notes
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