HRID615515

反应详情

EQUATION

反应方程式

HRID 615515 的结构方程式

PROCEDURE

实验过程

The process for the key intermediate in the copending application is exemplified as follows: 6-methoxy-1-naphthalenecarboxylic acid methyl ester is reacted with iodine and iodic acid in the presence of 98% sulfuric acid to give 5-iodo-6-methoxy-1-naphthalenecarboxylic acid methyl ester, which in turn is reacted with trifluoromethyl iodide and copper powder in a stainless steel autoclave to give 6-methoxy-5-(trifluoromethyl)-1-naphthalenecarboxylic acid methyl ester. Hydrolysis of the latter compound with dilute aqueous sodium hydroxide gives 6-methoxy-5-(trifluoromethyl)-1-naphthalenecarboxylic acid, one of the key intermediate noted hereinbefore. The latter compound also can be named 5-(trifluoromethyl)-6-methoxy-1-naphthalenecarboxylic acid.