HRID617159

反应详情

EQUATION

反应方程式

HRID 617159 的结构方程式

PROCEDURE

实验过程

The same procedure as in Example 48 was repeated, using 335 mg (0.61 mmol) of Compound 47 obtained in Example 47, except that propyl iodide was used in place of methyl iodide, to give 164 mg (yield: 46%) of Compound 49 as white crystals.