HRID617160

反应详情

EQUATION

反应方程式

HRID 617160 的结构方程式

PROCEDURE

实验过程

The same procedure as in Example 48 was repeated, using 335 mg (0.61 mmol) of Compound 47 obtained in Example 47, except that isopropyl iodide was used in place of methyl iodide, to give 112 mg (yield: 31%) of Compound 50 as white crystals.