Hydrochloric Acid → HCID 21851265, compound

HRID 617166Notes

Reaction equation

HRID 617166 reaction equation
[CH2:1]([O:3][C:4]1[CH:5]=[C:6]2[C:11](=[CH:12][C:13]=1[O:14][CH2:15][C:16]([O:18]CC)=[O:17])[N:10]=[C:9]([N:21]1[CH2:26][CH2:25][O:24][CH2:23][CH2:22]1)[N:8]=[C:7]2[N:27]1[CH2:32][CH2:31][CH:30]([N:33]2[C:42](=[O:43])[C:41]3[C:36](=[CH:37][CH:38]=[C:39]([CH3:44])[CH:40]=3)[N:35]([CH3:45])[C:34]2=[O:46])[CH2:29][CH2:28]1)[CH3:2].[OH-].[Na+].Cl.CCOCC>CO>[C:16]([CH2:15][O:14][C:13]1[CH:12]=[C:11]2[C:6]([C:7]([N:27]3[CH2:32][CH2:31][CH:30]([N:33]4[C:42](=[O:43])[C:41]5[C:36](=[CH:37][CH:38]=[C:39]([CH3:44])[CH:40]=5)[N:35]([CH3:45])[C:34]4=[O:46])[CH2:29][CH2:28]3)=[N:8][C:9]([N:21]3[CH2:26][CH2:25][O:24][CH2:23][CH2:22]3)=[N:10]2)=[CH:5][C:4]=1[O:3][CH2:1][CH3:2])([OH:18])=[O:17]

Participants

6

Procedure

In 30 ml of methanol was dissolved 900 mg (1.42 mmol) of Compound 54 obtained in Example 54, 15 ml of 2N-sodium hydroxide was added, and the mixture was stirred under heating at reflux for 4 hour. After cooling, 4N-hydrochloric acid was added to the reaction mixture and the mixtute was neutralized and subjected to extraction with chloroform. The organic layer was washed, dried and concentrated to give the residue. Ether was added to the above residue to give the precipitate which was collected by filtration and dried to give 870 mg (yield: 100%) of Compound 56 as white crystals.

Workup

  1. additionwas added
  2. temperatureunder heating
  3. temperatureat reflux for 4 hour
  4. temperatureAfter cooling
  5. extractionsubjected to extraction with chloroform
  6. washThe organic layer was washed
  7. customdried
  8. concentrationconcentrated
  9. customto give the residue
  10. customto give the precipitate which
  11. filtrationwas collected by filtration
  12. customdried

Sources & evidence

ORD record
ord-787565e4fbe248da9395e74212334636
Source dataset
uspto-grants-1999_09
Patent number
US05948784

Reaction notes

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