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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 623182Generated: October 29, 2026

2,2,2-Trifluoroethanol → Aluminum trifluoroethoxide

https://huagongshe.com/reaction/623182

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2,2,2-TrifluoroethanolHCID 6409—
ReactantAluminumHCID 5359268—
ReactantEthylaluminum Di-(2,2,2-trifluoroethoxide)HCID 21290501—
SolventDichloromethaneHCID 6344—
ProductAluminum trifluoroethoxideHCID 19419412—

Reaction Conditions

Temperature40 °C

Reaction Steps

In a flask, under a nitrogen blanket, were placed 7.43 g (0.29 mole) of the product of Example 2 and 50 ml methylene chloride. Then, 3.07 g (0.031 mole) of 2,2,2-trifluoroethanol was added in a way so as to maintain the temperature at about 40° C. After the addition was complete, the flask was placed in an oil bath at 60° C. and most of the methylene chloride was evaporated. The product was allowed to stand at the same temperature for one hour and the remainder of the solvent stripped off under vacuum. There was obtained 9.09 g (95% of theoretical yield) of a white crystalline solid. Analysis for aluminum showed 8.36% Al. The theoretical value was 8.33%.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04774214
Source datasetuspto-grants-1988_09
ORD IDord-eaf0d6b1241348d38872673ce5db75b4
Source noteuspto-grants-1988_09