2,2,2-Trifluoroethanol → Aluminum trifluoroethoxide

HRID 623182Notes

Reaction equation

HRID 623182 reaction equation
[F:1][C:2]([F:6])([F:5])[CH2:3][O-:4].[F:7][C:8]([F:12])([F:11])[CH2:9][O-:10].C([Al+2:15])C.[F:16][C:17]([F:21])([F:20])[CH2:18][OH:19].[Al]>C(Cl)Cl>[F:1][C:2]([F:6])([F:5])[CH2:3][O-:4].[F:7][C:8]([F:12])([F:11])[CH2:9][O-:10].[F:16][C:17]([F:21])([F:20])[CH2:18][O-:19].[Al+3:15]

Participants

5

Reactant 3

HCID 64092,2,2-TrifluoroethanolHCID 5359268AluminumHCID 21290501Ethylaluminum Di-(2,2,2-trifluoroethoxide)

Product 1

HCID 19419412Aluminum trifluoroethoxide

Reagents, catalysts & solvents 1

HCID 6344DichloromethaneSolvent2×

Conditions

Temperature
40 °C

Procedure

In a flask, under a nitrogen blanket, were placed 7.43 g (0.29 mole) of the product of Example 2 and 50 ml methylene chloride. Then, 3.07 g (0.031 mole) of 2,2,2-trifluoroethanol was added in a way so as to maintain the temperature at about 40° C. After the addition was complete, the flask was placed in an oil bath at 60° C. and most of the methylene chloride was evaporated. The product was allowed to stand at the same temperature for one hour and the remainder of the solvent stripped off under vacuum. There was obtained 9.09 g (95% of theoretical yield) of a white crystalline solid. Analysis for aluminum showed 8.36% Al. The theoretical value was 8.33%.

Workup

  1. customIn a flask, under a nitrogen blanket, were placed
  2. additionAfter the addition
  3. customwas evaporated
  4. customThere was obtained
  5. custom9.09 g (95% of theoretical yield) of a white crystalline solid

Sources & evidence

ORD record
ord-eaf0d6b1241348d38872673ce5db75b4
Source dataset
uspto-grants-1988_09
Patent number
US04774214

Reaction notes

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