Bromine → HCID 14822963, compound

Participants

Reaction Steps

In substantial accordance with the procedure described in Example 1(2), dineophyl-di(3-thienyl)tin (80 g, 0.145 mol) obtained above was reacted with bromine to give crude dineophyl-3-thienyltin bromide, which was then reacted with sodium fluoride. The resulting product was recrystallized from n-hexane to provide 21.5 g of dineophyl-3-thienyltin fluoride as a white solid.

Provenance & Evidence