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HRID629835

反应详情

EQUATION

反应方程式

HRID 629835 的结构方程式

REACTANTS

反应物

3
结构：CO[C@@]12CC[C@@]3(C[C@@H]1[C@](C)(O)C(C)(C)C)[C@H]1Cc4ccc(O)c5c4[C@@]3(CCN1CC1CC1)[C@H]2O5
HCID9848990

未命名化合物

结构：CC(C)(C)[C@@](C)(O)[C@H]1C[C@@H]2[C@H]3Cc4c5c(c(O)c6c4[C@@]2(CCN3CC2CC2)[C@@H](O6)[C@H]1O)CC5
HCID86711659

未命名化合物

结构：C=CCN1CC[C@]23c4c5c6c(c(O)c4O[C@H]2[C@@H](OC)[C@@H]([C@](C)(O)C(C)(C)C)C[C@@H]3[C@H]1C5)CC6
HCID86711662

未命名化合物

PRODUCTS

生成物

1
结构：C=CCN1CC[C@]23c4c5c6c(c(O)c4O[C@H]2[C@@H](O)[C@@H]([C@](C)(O)C(C)(C)C)C[C@@H]3[C@H]1C5)CC6
HCID86711663

未命名化合物

收率 75.8%

PROCEDURE

实验过程

Compound 16 was synthesized similar to the procedure described in Example 1 for the preparation of compound 2 using compound 15 rather than compound 1. After column chromatography, 4.0 g of compound 16 (75.8%) was obtained with a purity of 98.5%.

WORKUP

后处理

  1. customCompound 16 was synthesized similar to the procedure