4-Hydroxy-9-fluorenone → 9H-fluoren-4-ol
Reaction equation
[OH:1][C:2]1[C:14]2[C:13]3[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=3)[C:7](=O)[C:6]=2[CH:5]=[CH:4][CH:3]=1.[H][H]>CCOC(C)=O.CCO.[Pd]>[OH:1][C:2]1[C:14]2[C:13]3[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=3)[CH2:7][C:6]=2[CH:5]=[CH:4][CH:3]=1Participants
6
Reactant 2
Product 1
Reagents, catalysts & solvents 3
Procedure
A partial solution of 196.2 mg (1 mmol) of 4-hydroxy-fluoren-9-one in 2 mL EtOAc and 3 mL EtOH with 40 mg 10% Pd/C was stirred under a balloon of hydrogen for 27.5 hours. The catalyst was removed by filtration through celite, washed well with EtOAc, and the filtrate evaporated. The residue was purified by plate layer chromatography with CH2Cl2-EtOAc(50:1) to give 102.7 mg of the title substance.
Workup
- customThe catalyst was removed by filtration through celite
- washwashed well with EtOAc
- customthe filtrate evaporated
- customThe residue was purified by plate layer chromatography with CH2Cl2-EtOAc(50:1)
- customto give 102.7 mg of the title substance
Sources & evidence
- ORD record
- ord-79430c54e25a4a7e9fc6f6fe2fcf2421
- Source dataset
- uspto-grants-2001_08
- Patent number
- US06277843B1
Reaction notes
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