Hydrochloric Acid → 6-Phenyl-1,3-dihydro-indol-2-one
Reaction equation
CS[CH:3]1[C:11]2[C:6](=[CH:7][C:8]([C:12]3[CH:17]=[CH:16][CH:15]=[CH:14][CH:13]=3)=[CH:9][CH:10]=2)[NH:5][C:4]1=[O:18].[Sn].Cl>C(O)C>[C:12]1([C:8]2[CH:7]=[C:6]3[C:11]([CH2:3][C:4](=[O:18])[NH:5]3)=[CH:10][CH:9]=2)[CH:13]=[CH:14][CH:15]=[CH:16][CH:17]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
A mixture of 3.5 g. (0.014 mole) of 3-methylthio-6-phenylindolin-2-one, 7 g. of tin, 10 ml. of concentrated hydrochloric acid and 50 ml. of ethanol was refluxed 4 hours under nitrogen. The hot mixture was filtered and the filtrate concentrated to give a tan solid. The solid was further purified by vacuum sublimation at 0.01 mm. and 200° C. and then crystallized from benzene to give 0.5 g. (17%) of product as a white solid which melted at 173°-175° C.
Workup
- additionA mixture of 3.5 g
- filtrationThe hot mixture was filtered
- concentrationthe filtrate concentrated
- customto give a tan solid
- customThe solid was further purified by vacuum sublimation at 0.01 mm
- customand 200° C. and then crystallized from benzene
- customto give 0.5 g
Sources & evidence
- ORD record
- ord-cccf1a282f784ed997a41275a48bbab8
- Source dataset
- uspto-grants-1987_06
- Patent number
- US04670566
Reaction notes
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