HRID65349

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID10868

Dicyclohexylcarbodiimide

C13H22N2

HCID75771

1-Hydroxybenzotriazole

C6H5N3O

HCID81531

Diisopropylethylamine

C8H19N

结构：COC(=O)C[C@H](O)[C@H](CC(C)C)NC(=O)[C@H](C)NC(=O)[C@@H](NC(=O)[C@@H](N)CC(C)C)C(C)C.Cl

HCID131714869

未命名化合物

结构：CC(C)(C)OC(=O)N[C@@H](Cc1ccccc1)C(=O)N[C@@H](Cc1c[nH]cn1)C(=O)O

HCID178454152

未命名化合物

PRODUCTS

生成物

结构：COC(=O)C[C@H](O)[C@H](CC(C)C)NC(=O)[C@H](C)NC(=O)[C@@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@H](Cc1c[nH]cn1)NC(=O)[C@H](Cc1ccccc1)NC(=O)OC(C)(C)C)C(C)C

HCID178500733

未命名化合物

PROCEDURE

实验过程

In a manner analogous to that described in Example 1, using as starting materials 52 mg of BOC-Phe-His-OH, 60 mg of H-Leu-Val-Ala-Sta-OCH3.HCl, 18 mg of HOBT, 0.24 ml of ethyldiisopropylamine and 34 mg of DCCI, the title compound is obtained in the form of a colourless powder after flash chromatography (30 g of silica gel 60, 40-63 μm, system N8). Rf(N9)=0.38.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-f3e6f5a68a3b487caa7a5b1363b9e883
来源数据集: uspto-grants-1986_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04613676
来源说明: uspto-grants-1986_09

反应 SMILES

[NH:1]([C:23]([O:25][C:26]([CH3:29])([CH3:28])[CH3:27])=[O:24])[C@H:2]([C:10]([NH:12][C@H:13]([C:20](O)=[O:21])[CH2:14][C:15]1[N:19]=[CH:18][NH:17][CH:16]=1)=[O:11])[CH2:3][C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1.[NH2:30][C@H:31]([C:36]([NH:38][C@H:39]([C:43]([NH:45][C@H:46]([C:48]([NH:50][C@H:51]([C@H:56]([CH2:58][C:59]([O:61][CH3:62])=[O:60])[OH:57])[CH2:52][CH:53]([CH3:55])[CH3:54])=[O:49])[CH3:47])=[O:44])[CH:40]([CH3:42])[CH3:41])=[O:37])[CH2:32][CH:33]([CH3:35])[CH3:34].Cl.C1C=CC2N(O)N=NC=2C=1.C(N(C(C)C)C(C)C)C.C1CCC(N=C=NC2CCCCC2)CC1>>[NH:1]([C:23]([O:25][C:26]([CH3:28])([CH3:27])[CH3:29])=[O:24])[C@H:2]([C:10]([NH:12][C@H:13]([C:20]([NH:30][C@H:31]([C:36]([NH:38][C@H:39]([C:43]([NH:45][C@H:46]([C:48]([NH:50][C@H:51]([C@H:56]([CH2:58][C:59]([O:61][CH3:62])=[O:60])[OH:57])[CH2:52][CH:53]([CH3:54])[CH3:55])=[O:49])[CH3:47])=[O:44])[CH:40]([CH3:41])[CH3:42])=[O:37])[CH2:32][CH:33]([CH3:35])[CH3:34])=[O:21])[CH2:14][C:15]1[N:19]=[CH:18][NH:17][CH:16]=1)=[O:11])[CH2:3][C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1