HRID65370

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID10868

Dicyclohexylcarbodiimide

C13H22N2

HCID75771

1-Hydroxybenzotriazole

C6H5N3O

结构：CC[C@H](C)[C@H](NC(=O)[C@@H](NC(=O)[C@@H](N)CC(C)C)C(C)C)C(=O)O.[NH-]CCc1c[nH]c2ccccc12

HCID131714913

未命名化合物

结构：O=C(N[C@@H](Cc1ccccc1)C(=O)N[C@@H](Cc1c[nH]cn1)C(=O)O)OCc1ccccc1

HCID178523857

未命名化合物

PRODUCTS

生成物

结构：CC[C@H](C)[C@H](NC(=O)[C@@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@H](Cc1c[nH]cn1)NC(=O)[C@H](Cc1ccccc1)NC(=O)OCc1ccccc1)C(C)C)C(=O)O.[NH-]CCc1c[nH]c2ccccc12

HCID178455951

未命名化合物

PROCEDURE

实验过程

In a manner analogous to that described in Example 1, using as starting materials 92 mg of Z-Phe-His-OH, 79 mg of H-Leu-Val-Ile-2-(3-indolyl)-ethyl amide, 32 mg of HOBt and 44 mg of DCCI, the title compound is obtained after flash chromatography (65 g of silica gel 60, 40-63 μm, eluant system B7). Rf (B7)=0.34.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-cbaca4ba7a2844679f2ae32055fe394d
来源数据集: uspto-grants-1986_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04613676
来源说明: uspto-grants-1986_09

反应 SMILES

[NH:1]([C:23]([O:25][CH2:26][C:27]1[CH:32]=[CH:31][CH:30]=[CH:29][CH:28]=1)=[O:24])[C@H:2]([C:10]([NH:12][C@H:13]([C:20](O)=[O:21])[CH2:14][C:15]1[N:19]=[CH:18][NH:17][CH:16]=1)=[O:11])[CH2:3][C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1.[NH2:33][C@H:34]([C:39]([NH:41][C@H:42]([C:46]([NH:48][C@H:49]([C:54]([OH:56])=[O:55])[C@H:50]([CH2:52][CH3:53])[CH3:51])=[O:47])[CH:43]([CH3:45])[CH3:44])=[O:40])[CH2:35][CH:36]([CH3:38])[CH3:37].[NH:57]1[C:65]2[C:60](=[CH:61][CH:62]=[CH:63][CH:64]=2)[C:59]([CH2:66][CH2:67][NH-:68])=[CH:58]1.C1C=CC2N(O)N=NC=2C=1.C1CCC(N=C=NC2CCCCC2)CC1>>[NH:1]([C:23]([O:25][CH2:26][C:27]1[CH:32]=[CH:31][CH:30]=[CH:29][CH:28]=1)=[O:24])[C@H:2]([C:10]([NH:12][C@H:13]([C:20]([NH:33][C@H:34]([C:39]([NH:41][C@H:42]([C:46]([NH:48][C@H:49]([C:54]([OH:56])=[O:55])[C@H:50]([CH2:52][CH3:53])[CH3:51])=[O:47])[CH:43]([CH3:44])[CH3:45])=[O:40])[CH2:35][CH:36]([CH3:37])[CH3:38])=[O:21])[CH2:14][C:15]1[N:19]=[CH:18][NH:17][CH:16]=1)=[O:11])[CH2:3][C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1.[NH:57]1[C:65]2[C:60](=[CH:61][CH:62]=[CH:63][CH:64]=2)[C:59]([CH2:66][CH2:67][NH-:68])=[CH:58]1