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HRID654279

反应详情

EQUATION

反应方程式

HRID 654279 的结构方程式

REACTANTS

反应物

2
结构：NCCO
HCID700

Ethanolamine

C2H7NO

结构：CCCCCCCCCCCCCCCC(=O)O
HCID985

Hexadecanoic acid

C16H32O2

PRODUCTS

生成物

1
结构：CCCCCCCCCCCCCCCC1=NCCO1
HCID12396777

2-Pentadecyl-4,5-dihydro-1,3-oxazole

C18H35NO

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCCC[O-].CCCC[O-].CCCC[O-].CCCC[O-].[Ti+4]
催化剂HCID21801

Titanium(IV) n-butoxide

C16H36O4Ti

PROCEDURE

实验过程

Following the procedure described in Example 2, palmitic acid was reacted with ethanolamine in the presence of titanium tetrabutylate to form 2-pentadecyl-2-oxazoline. The quantities used were as follows: