HRID65502

反应详情

EQUATION

反应方程式

HRID 65502 的结构方程式

PROCEDURE

实验过程

In a 100 ml apparatus, there were combined 8.6 g (0.75 mol) of MeSiHCl2, 7.1 g (0.075 mol) of Me2SiHCl, and 6.8 g (0.075 mol) of methallyl chloride. Pt catalyst solution (0.01 ml) was added at 32° causing an exothermic reaction to 57° C. and completion in 10 min. Distillation yielded 54.0% of Me2SiClCH2CHMeCH2Cl and 19.6% of MeSiCl2CH2CHMeCH2Cl, indicating that at the equimolar level, neither MeSiHCl2 nor Me2SiHCl is a very effective promoter for reactions of the other with methallyl chloride, in terms of yield, but that reaction rates are increased.

WORKUP

后处理

  1. customan exothermic reaction to 57° C.
  2. distillationDistillation