Methanol → (7-Fluoro-quinolin-6-yl)-acetic acid methyl ester
Reaction equation
[F:1][C:2]1[CH:11]=[C:10]2[C:5]([CH:6]=[CH:7][CH:8]=[N:9]2)=[CH:4][C:3]=1[CH2:12][C:13]([OH:15])=[O:14].OS(O)(=O)=O.[CH3:21]O>C(OCC)(=O)C>[CH3:21][O:14][C:13](=[O:15])[CH2:12][C:3]1[CH:4]=[C:5]2[C:10](=[CH:11][C:2]=1[F:1])[N:9]=[CH:8][CH:7]=[CH:6]2Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of (7-fluoro-quinolin-6-yl)-acetic acid (13.4 g, 65.36 mmol) in methanol (140 mL) was added conc.H2SO4 (3.5 mL, 68.63 mmol). The reaction mixture was concentrated to give a brown residue, which was diluted with 100 ml of ethyl acetate, washed with sat. aq. NaHCO3 and brine, then the organic layer was dried over anhydrous Na2SO4, and concentrated to give (7-fluoro-quinolin-6-yl)-acetic acid methyl ester as yellow solid (14.0 g, yield: 98%).
Workup
- concentrationThe reaction mixture was concentrated
- customto give a brown residue, which
- washwashed with sat. aq. NaHCO3 and brine
- dry with materialthe organic layer was dried over anhydrous Na2SO4
- concentrationconcentrated
Sources & evidence
- ORD record
- ord-a246ffe110d644489761b10db1a7e158
- Source dataset
- uspto-grants-2011_12
- Patent number
- US08071581B2
Reaction notes
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