HRID660886

反应详情

EQUATION

反应方程式

HRID 660886 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

2.90 g (7.60 mmol) of the ester from Example 153A are dissolved in 77 ml methanol and treated with a 1 N solution of lithium hydroxide in water (30.3 ml, 30.4 mmol). The mixture is stirred overnight at RT, then freed of methanol on the rotary evaporator and diluted with 200 ml water. After addition of 1 N hydrochloric acid to a pH value of 2, the product precipitates out as a white solid, which is isolated by filtration and drying in high vacuum. 2.45 g (88% of theory) of the title compound are obtained.

WORKUP

后处理

  1. customfreed of methanol on the rotary evaporator
  2. additiondiluted with 200 ml water
  3. additionAfter addition of 1 N hydrochloric acid to a pH value of 2
  4. customthe product precipitates out as a white solid
  5. customwhich is isolated by filtration
  6. customdrying in high vacuum