Water → 3-(2-Chloro-4-cyanophenyl)propanol
Reaction equation
[Cl:1][C:2]1[CH:7]=[C:6]([C:8]#[N:9])[CH:5]=[CH:4][C:3]=1[CH2:10][CH2:11][C:12](O)=[O:13].[H]1[BH2][H][BH2]1.O>C1COCC1>[Cl:1][C:2]1[CH:7]=[C:6]([C:8]#[N:9])[CH:5]=[CH:4][C:3]=1[CH2:10][CH2:11][CH2:12][OH:13]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To 3-(2-chloro-4-cyanophenyl)-propanoic acid (14.3 g, 0.068 mol) in 70 mL of dry THF at -18° C. was added B2H6 (72 ml, 0.068 mol) in THF. The mixture was stirred at room temperature overnight. After addition of water, the layers were separated and the aqueous phase was extracted with ether. Evaporation and distillation gave 3-(2-chloro-4-cyanophenyl)propanol as an oil: 11.0 g; bp 55°-60° C. (0.005 mm Hg). Anal. calcd for C10H10ClNO: C, 61.39; H, 5.15; N, 7.16. Found: C, 61.02; H, 5.19; N, 6.76.
Workup
- customthe layers were separated
- extractionthe aqueous phase was extracted with ether
- customEvaporation and distillation
Sources & evidence
- ORD record
- ord-9612dc692cdc459a8cbe8cc3dd553fcb
- Source dataset
- uspto-grants-1982_08
- Patent number
- US04347382
Reaction notes
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