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HRID69848

反应详情

EQUATION

反应方程式

HRID 69848 的结构方程式

REACTANTS

反应物

2
结构：O=[N+]([O-])c1cc(Cl)ccc1F
HCID67660

4-Chloro-1-fluoro-2-nitrobenzene

C6H3ClFNO2

结构：CC(C)(C)OC(=O)N1CCNCC1
HCID143452

tert-Butyl piperazine-1-carboxylate

C9H18N2O2

PRODUCTS

生成物

1
结构：CC(C)(C)OC(=O)N1CCN(c2ccc(Cl)cc2[N+](=O)[O-])CC1
HCID69042278

1,1-Dimethylethyl 4-(4-chloro-2-nitrophenyl)-1-piperazinecarboxylate

C15H20ClN3O4

收率 95%

PROCEDURE

实验过程

Method 1 was followed using 1 eq each of 4-chloro-1-fluoro-2-nitrobenzene, 1-Boc-piperazine, and TEA yielding tert-butyl 4-(4-chloro-2-nitrophenyl)piperazine-1-carboxylate (95%). LCMS (m/z): 342.0 (MH+); LC Rt=3.50 min.