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HRID72532

反应详情

EQUATION

反应方程式

HRID 72532 的结构方程式

REACTANTS

反应物

2
结构：COC(=O)c1ccc([C@H](C)N)cc1.Cl
HCID57462942

Methyl 4-[(1S)-1-aminoethyl]benzoate--hydrogen chloride (1/1)

C10H14ClNO2

结构：O=C(O)c1cc(Cl)cnc1N1CCC(Oc2ccc(F)cc2)C1
HCID67958506

未命名化合物

PRODUCTS

生成物

1
结构：COC(=O)c1ccc([C@H](C)NC(=O)c2cc(Cl)cnc2N2CCC(Oc3ccc(F)cc3)C2)cc1
HCID67958668

未命名化合物

收率 40.2%

PROCEDURE

实验过程

The title compound (D193) (64 mg) was prepared according to the experimental procedure described in Description 146 starting from 5-chloro-2-(3-(4-fluorophenoxy)pyrrolidin-1-yl)nicotinic acid (D138) (110 mg, 0.320 mmol), and (S)-methyl 4-(1-aminoethyl)benzoate (D3) (68.82 mg, 0.320 mmol) MS: (ES/+) m/z: 499.2 [MH+] C26H25ClFN3O4 requires 497.15