4-Fluorobenzoyl chloride → HCID 59751437, compound
Reaction equation
[CH3:1][S:2]([C:5]1[CH:10]=[CH:9][C:8]([C:11]2[C:12]([O:22][C:23]3[CH:28]=[CH:27][C:26]([O:29][CH2:30][CH2:31][N:32]4[CH2:37][CH2:36][CH2:35][CH2:34][CH2:33]4)=[CH:25][CH:24]=3)=[C:13]3[C:18](=[CH:19][CH:20]=2)[CH:17]=[C:16]([OH:21])[CH:15]=[CH:14]3)=[CH:7][CH:6]=1)(=[O:4])=[O:3].[F:38][C:39]1[CH:47]=[CH:46][C:42]([C:43](Cl)=[O:44])=[CH:41][CH:40]=1.C(=O)(O)[O-].[Na+]>ClCCl>[CH3:1][S:2]([C:5]1[CH:6]=[CH:7][C:8]([C:11]2[C:12]([O:22][C:23]3[CH:28]=[CH:27][C:26]([O:29][CH2:30][CH2:31][N:32]4[CH2:37][CH2:36][CH2:35][CH2:34][CH2:33]4)=[CH:25][CH:24]=3)=[C:13]3[C:18](=[CH:19][CH:20]=2)[CH:17]=[C:16]([O:21][C:43](=[O:44])[C:42]2[CH:46]=[CH:47][C:39]([F:38])=[CH:40][CH:41]=2)[CH:15]=[CH:14]3)=[CH:9][CH:10]=1)(=[O:4])=[O:3]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Dissolve the compound of Example 3 (111 mg, 0.21 mmol) in dichloromethane (2 mL). Add 4-fluorobenzoyl chloride (30 μL, 0.25 mmol) dropwise. After stirring for 10 minutes, pour the reaction mixture into saturated aqueous sodium bicarbonate (10 mL) and extract with dichloromethane (10 mL). Dry the organic layer with sodium sulfate, filter and concentrate in vacuo. Chromatograph the residue on a SiO2 column eluting with methanol in dichloromethane (0 to 3%) to give 99 mg of the title compound (73%): mass spectrum (ion spray): m/z=640.3 (M+H).
Workup
- extractionextract with dichloromethane (10 mL)
- dry with materialDry the organic layer with sodium sulfate
- filtrationfilter
- concentrationconcentrate in vacuo
- washChromatograph the residue on a SiO2 column eluting with methanol in dichloromethane (0 to 3%)
Sources & evidence
- ORD record
- ord-c53bad36b77f40a58e5cd42a254ba719
- Source dataset
- uspto-grants-2009_09
- Patent number
- US07585977B2
Reaction notes
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