反应详情

Using a procedure analogous to that used to prepare 2B, 11B (434 mg, 1.15 mmol) was reacted with NaOH to give 11C (170 mg, 48%) as a solid. 1H NMR (400 MHz, THF-d8) δ 2.98 (t, J=7.03 Hz, 2 H), 4.38 (t, J=6.81 Hz, 2 H), 7.10 (s, 2 H), 7.22 (d, J=7.91 Hz, 1 H), 7.30 (d, J=7.47 Hz, 1 H), 7.39 (t, J=7.91 Hz, 1 H), 7.68 (d, J=8.35 Hz, 1 H), 7.73 (d, J=8.35 Hz, 2 H), 7.87 (s, 1 H), 9.11 (s, 1 H).