Tetrahydro-4H-pyran-4-one → HCID 10312268, compound

HRID 736688Notes

Reaction equation

HRID 736688 reaction equation
FC(F)(F)C(O)=O.FC(F)(F)C(O)=O.[CH3:15][C:16]1[CH:25]=[C:24]([CH2:26][O:27][C:28]2[CH:52]=[CH:51][C:31]([C:32]([NH:34][CH2:35][C:36]3([CH:45]4[CH2:50][CH2:49][NH:48][CH2:47][CH2:46]4)[C:41](=[O:42])[NH:40][C:39](=[O:43])[NH:38][C:37]3=[O:44])=[O:33])=[CH:30][CH:29]=2)[C:23]2[C:18](=[CH:19][CH:20]=[CH:21][CH:22]=2)[N:17]=1.[O:53]1[CH2:58][CH2:57][C:56](=O)[CH2:55][CH2:54]1>>[CH3:15][C:16]1[CH:25]=[C:24]([CH2:26][O:27][C:28]2[CH:29]=[CH:30][C:31]([C:32]([NH:34][CH2:35][C:36]3([CH:45]4[CH2:50][CH2:49][N:48]([CH:56]5[CH2:57][CH2:58][O:53][CH2:54][CH2:55]5)[CH2:47][CH2:46]4)[C:37](=[O:44])[NH:38][C:39](=[O:43])[NH:40][C:41]3=[O:42])=[O:33])=[CH:51][CH:52]=2)[C:23]2[C:18](=[CH:19][CH:20]=[CH:21][CH:22]=2)[N:17]=1

Participants

3

Reactant 2

HCID 121599Tetrahydro-4H-pyran-4-oneHCID 86590477HCID 86590477, compound

Product 1

HCID 10312268HCID 10312268, compoundYield 22%

Procedure

Following the procedure analogous to that used in reaction (9), the compound from Example 29 was reacted with tetrahydro-4H-pyran-4-one for 5 days to provide the title compound (5 mg, 22%). MS found: (M+H)+=600.4.

Sources & evidence

ORD record
ord-1798bdeb862847d8a3df3ab0247d5409
Source dataset
uspto-grants-2009_09
Patent number
US07595317B2

Reaction notes

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