Formate → HCID 12849808, compound
Reaction equation
C([O-])=O.[CH3:4][O:5][C:6]1[CH:15]=[CH:14][C:13]2[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=2)[C:7]=1[OH:16].[NH2:17][C:18]1[N:23]=[C:22]([NH2:24])[C:21]([CH2:25]O)=[CH:20][N:19]=1.Cl>C(O)(=O)C>[NH2:17][C:18]1[N:23]=[C:22]([NH2:24])[C:21]([CH2:25][C:14]2[C:13]3[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=3)[C:7]([OH:16])=[C:6]([O:5][CH3:4])[CH:15]=2)=[CH:20][N:19]=1Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
The formate of 2-methoxy-1-naphthol (J. E. Oatis, Jr., M. P. Russell, D. R. Knapp and T. Walle, J. Med. Chem. 1981, 24, 309) (7.23 g, 30.3 mmol), 2,4-diamino-5-hydroxymethylpyrimidine (4.35 g, 30.3 mmol), concentrated hydrochloric acid (4.2 mL) and glacial acetic acid (60 mL) were refluxed 2 hr. The resulting dark solution was evaporated to dryness and the residue dissolved in water and neutralized with ammonia. The resulting tan precipitate (5.2 g) was recrystallized from aqueous ethanol containing a slight excess of hydrochloric acid to give title compound as tan powder (2.83 g, 28%); mp ca. 290°-300° dec. Anal. Calcd for C16H16N4O2.HCl: C, 57.75; H, 5.15; N, 16.84; Cl, 10.65. Found: C, 57.62; H, 5.21; N, 16.79; Cl, 10.61.
Workup
- customThe resulting dark solution was evaporated to dryness
- dissolutionthe residue dissolved in water and neutralized with ammonia
- customThe resulting tan precipitate (5.2 g) was recrystallized from aqueous ethanol containing a slight excess of hydrochloric acid
Sources & evidence
- ORD record
- ord-dd3f29c8c78b48d8a296536706b9f3d8
- Source dataset
- uspto-grants-1986_07
- Patent number
- US04603136
Reaction notes
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