Acetone → methyl cyclooct-4-ene carboxylate
Reaction equation
[CH:1]1([C:9]([OH:11])=[O:10])[CH2:8][CH2:7][CH2:6][CH:5]=[CH:4][CH2:3][CH2:2]1.[CH3:12]C(C)=O.C([O-])([O-])=O.[K+].[K+].CI>O>[CH:1]1([C:9]([O:11][CH3:12])=[O:10])[CH2:2][CH2:3][CH2:4][CH:5]=[CH:6][CH2:7][CH2:8]1Participants
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
A 50 mL, 3-neck round bottom flask was charged with cyclooct-4-ene carboxylic acid (0.517 g, 3.35 mmol, prepared as described below in Example 35) and 30 mL reagent-grade acetone and vigorously stirred for several minutes. K2CO3 (1.15 g, 8.32 mmol) was then added, followed by an excess of methyl iodide (4 mL). A reflux condenser (water temperature 5° C.) was then fitted to the flask and the reaction was gently refluxed overnight. The mixture was filtered, the filtrate was concentrated using a rotary evaporator, and the residue was purified by flash chromatography on silica (1:9 ethyl acetate:hexanes mobile phase) to give methyl cyclooct-4-ene carboxylate as a single isomer (0.560 g, 99%). A copolymer of methyl cyclooct-4-ene carboxylate and cyclooctene, prepared similarly to polymer 15 at room temperature, would have the following features: The end groups R2 and R3 would be H or CH3. For this polymer, e and f would be derived from methyl cyclooct-4-ene carboxylate and would equal 3 and 4, respectively; d would derive from cyclooctene and would equal 8. The run lengths would therefore be: rHH=(3+3)+8z; rHT=(3+4)+8z; and rTT=(4+4)+8z; therefore rtotal=(6+8z), (7+8z), (8+8z).
Workup
- filtrationThe mixture was filtered
- concentrationthe filtrate was concentrated
- customa rotary evaporator
- customthe residue was purified by flash chromatography on silica (1:9 ethyl acetate:hexanes mobile phase)
Sources & evidence
- ORD record
- ord-3f1aac90f8124c9194da2a7fdc8ef5ab
- Source dataset
- uspto-grants-2008_07
- Patent number
- US07402642B2
Reaction notes
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