HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 749321Generated: October 29, 2026
Acetone → methyl cyclooct-4-ene carboxylate
https://huagongshe.com/reaction/749321
Participants
| Role | Name | HCID | Charge |
|---|
| Reactant | Acetone | HCID 180 | — |
| Reactant | Methyl iodide | HCID 6328 | — |
| Reactant | Potassium Carbonate | HCID 11430 | — |
| Reactant | HCID 290788 | HCID 290788 | — |
| Solvent | Water | HCID 962 | — |
| Product | methyl cyclooct-4-ene carboxylate | HCID 273849 | — |
Reaction Steps
A 50 mL, 3-neck round bottom flask was charged with cyclooct-4-ene carboxylic acid (0.517 g, 3.35 mmol, prepared as described below in Example 35) and 30 mL reagent-grade acetone and vigorously stirred for several minutes. K2CO3 (1.15 g, 8.32 mmol) was then added, followed by an excess of methyl iodide (4 mL). A reflux condenser (water temperature 5° C.) was then fitted to the flask and the reaction was gently refluxed overnight. The mixture was filtered, the filtrate was concentrated using a rotary evaporator, and the residue was purified by flash chromatography on silica (1:9 ethyl acetate:hexanes mobile phase) to give methyl cyclooct-4-ene carboxylate as a single isomer (0.560 g, 99%). A copolymer of methyl cyclooct-4-ene carboxylate and cyclooctene, prepared similarly to polymer 15 at room temperature, would have the following features: The end groups R2 and R3 would be H or CH3. For this polymer, e and f would be derived from methyl cyclooct-4-ene carboxylate and would equal 3 and 4, respectively; d would derive from cyclooctene and would equal 8. The run lengths would therefore be: rHH=(3+3)+8z; rHT=(3+4)+8z; and rTT=(4+4)+8z; therefore rtotal=(6+8z), (7+8z), (8+8z).
Provenance & Evidence
| DOI | 10.6084/m9.figshare.5104873.v1 |
|---|
| Patent number | US07402642B2 |
|---|
| Source dataset | uspto-grants-2008_07 |
|---|
| ORD ID | ord-3f1aac90f8124c9194da2a7fdc8ef5ab |
|---|
| Source note | uspto-grants-2008_07 |
|---|