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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 749560Generated: October 30, 2026

2-Fluoroethyl bromide → HCID 22235000, compound

https://huagongshe.com/reaction/749560

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-Fluoroethyl bromideHCID 12982—
ReactantSodium hydrideHCID 24758—
ReactantHCID 11345355HCID 11345355—
SolventDimethylformamideHCID 6228—
ProductHCID 22235000HCID 2223500048.8%

Reaction Steps

Using 0.47 g of (4-bromobenzyl)malononitrile, 5 ml of N,N-dimethylformamide, 0.12 g of sodium hydride (60% in oil), and 0.25 g of 1-bromo-2-fluoroethane, and according to the process described in the Production Example 1, there was obtained 0.27 g of 2-(4-bromobenzyl)-2-(2-fluoroethyl)malononitrile (the present compound (51)).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07402691B2
Source datasetuspto-grants-2008_07
ORD IDord-24c3f82b5f5241db9387b186efeb0491
Source noteuspto-grants-2008_07