2-Fluoroethyl bromide → HCID 22235000, compound

HRID 749560Notes

Reaction equation

HRID 749560 reaction equation
[Br:1][C:2]1[CH:13]=[CH:12][C:5]([CH2:6][CH:7]([C:10]#[N:11])[C:8]#[N:9])=[CH:4][CH:3]=1.[H-].[Na+].Br[CH2:17][CH2:18][F:19]>CN(C)C=O>[Br:1][C:2]1[CH:3]=[CH:4][C:5]([CH2:6][C:7]([CH2:17][CH2:18][F:19])([C:8]#[N:9])[C:10]#[N:11])=[CH:12][CH:13]=1

Participants

5

Reactant 3

HCID 129822-Fluoroethyl bromideHCID 24758Sodium hydrideHCID 11345355HCID 11345355, compound

Product 1

HCID 22235000HCID 22235000, compoundYield 48.8%

Reagents, catalysts & solvents 1

HCID 6228DimethylformamideSolvent

Procedure

Using 0.47 g of (4-bromobenzyl)malononitrile, 5 ml of N,N-dimethylformamide, 0.12 g of sodium hydride (60% in oil), and 0.25 g of 1-bromo-2-fluoroethane, and according to the process described in the Production Example 1, there was obtained 0.27 g of 2-(4-bromobenzyl)-2-(2-fluoroethyl)malononitrile (the present compound (51)).

Sources & evidence

ORD record
ord-24c3f82b5f5241db9387b186efeb0491
Source dataset
uspto-grants-2008_07
Patent number
US07402691B2

Reaction notes

Loading…