HRID76681

反应详情

EQUATION

反应方程式

HRID 76681 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

CONDITIONS

反应条件

温度
200 °C

PROCEDURE

实验过程

To a solution of 2-chloro-N4-(4-ethyloxyphenyl)-5-fluoro-4-pyrimidineamine (0.25 g, 0.93 mmol) in ethylene glycol (3 mL) under nitrogen at room temperature was added i-Pr2EtN, 0.93 mmol) followed by 3,4-ethylenedioxyaniline (0.17 g, 1.12 mmol). The reaction mixture was heated to 200° C. for 5 h and then cooled to room temperature. The mixture was partitioned between H2O (20 mL) and EtOAc (20 mL) and the aqueous layer was extracted with EtOAc (20 mL). The combined organic layers were dried (Na2SO4), filtered, and concentrated in vacuo. The crude brown solid was purified by chromatography (2:1 CHCl3/EtOAc) to afford N4-(4-ethyloxyphenyl)-N2-(3,4-ethylenedioxyphenyl)-5-fluoro-2,4-pyrimidinediamine (0.21 g, 60%) as a tan solid: Rf 0.42 (4:1 CHCl3/EtOAc); mp 163.8-167.2° C. (DSC); 1H NMR (300 MHz, CDCl3) δ 7.89 (d, J=2.8 Hz, 1H), 7.50-7.45 (m, 2H), 7.17 (d, J=2.5 Hz, 1H), 6.92-6.86 (m, 3H), 6.80-6.75 (m, 2H), 6.64 (bs, 1H), 4.26-4.21 (m, 4H), 4.03 (q, J=7.0, 2H), 1.42 (t, J=6.9 Hz, 3H); 13C NMR (75 MHz, CDCl3) δ 156.1, 150.6, 143.6, 142.8, 140.3, 140.0, 139.5, 139.3, 134.0, 130.8, 123.2, 117.2, 115.1, 113.6, 109.4, 64.6, 64.0, 15.1; IR (ATR) 3403 cm−1; ESI MS m/z 383 [C20H19FN4O3+H]+; HPLC (Method A) 98.1% (AUC), tR=12.0 min. Anal. Calcd for C20H19FN4O3: C, 62.82; H, 5.01; N, 14.65. Found: C, 62.06; H, 5.01; N, 14.35.

WORKUP

后处理

  1. temperaturecooled to room temperature
  2. customThe mixture was partitioned between H2O (20 mL) and EtOAc (20 mL)
  3. extractionthe aqueous layer was extracted with EtOAc (20 mL)
  4. dry with materialThe combined organic layers were dried (Na2SO4)
  5. filtrationfiltered
  6. concentrationconcentrated in vacuo
  7. customThe crude brown solid was purified by chromatography (2:1 CHCl3/EtOAc)