Sodium Hydroxide → 2,4-Dichloro-5-methoxyaniline
Reaction equation
CC([NH:4][C:5]1[C:10]([Cl:11])=[CH:9][C:8]([Cl:12])=[C:7]([O:13][CH3:14])[CH:6]=1)=O.[OH-].[Na+]>O.C(O)C>[Cl:11][C:10]1[CH:9]=[C:8]([Cl:12])[C:7]([O:13][CH3:14])=[CH:6][C:5]=1[NH2:4]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
In the manner of Example 2, Step C, the reaction of 37.4 g (0.16 mole) of 2,4-dichloro-5-methoxyacetanilide with 12.8 g (0.32 mole) of sodium hydroxide in 30 mL of water and 30 mL of ethanol produced 16.7 g of 2,4-dichloro-5-methoxyaniline.
Sources & evidence
- ORD record
- ord-b63b709da36d4403aeed1e3a384f5dcc
- Source dataset
- uspto-grants-1992_08
- Patent number
- US05136868
Reaction notes
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