HRID864715

反应详情

EQUATION

反应方程式

HRID 864715 的结构方程式

PROCEDURE

实验过程

Using the procedure described above in Preparation 1, 5.0 g (0.029 mol) of 6-chloroanthranilic acid and 2.75 ml (0.044 mol) of iodomethane were reacted in the presence of 4.08 g (0.073 mol) of powdered potassium hydroxide to give 4.22 g (78%) of methyl 6-chloroanthranilate as an oil.