HRID872159

反应详情

EQUATION

反应方程式

HRID 872159 的结构方程式

PROCEDURE

实验过程

Using the same general procedure as described for the preparation of 103, reaction of 105c (150 mg, 0.394 mmol) with 102f (201 mg, 0.433 mmol) afforded a crude product 105d which was used in the next step without purification.