2-Bromobiphenyl → HCID 69117197, compound

HRID 902388Notes

Reaction equation

HRID 902388 reaction equation
Br[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=1.[F:14][C:15]1[CH:20]=CC=[C:17](OC)[C:16]=1B(O)O.CO[CH2:28][CH2:29][O:30][CH3:31].O>>[F:14][C:15]1[CH:20]=[CH:28][C:29]([O:30][CH3:31])=[C:17]([C:2]2[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=2[C:8]2[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=2)[CH:16]=1

Participants

4

Reactant 3

HCID 163292-BromobiphenylHCID 3294524(2-Fluoro-6-methoxyphenyl)boronic acidHCID 18180031Water 1,2-dimethoxyethane

Product 1

HCID 69117197HCID 69117197, compoundYield 89%

Procedure

Treatment of 2-bromobiphenyl (6.85 g, 29.4 mmol) with 2-fluoro-6-methoxybenzene boronic acid (5.0 g, 29.4 mmol) in DME-water (5:1, 150 mL) according to the procedure described for Example 69, Step 1 provided 7.3 g (89%) of 5-fluoro-2-methoxy-2′-phenylbiphenyl as a colorless oil.

Sources & evidence

ORD record
ord-5823bdd479a84ca380280d5ada8416a5
Source dataset
uspto-grants-2008_04
Patent number
US07365095B2

Reaction notes

Loading…