Triethyl phosphite → Ethyl (diethoxyphosphoryl)ethoxyacetate
Reaction equation
Cl[CH2:2][CH2:3][O:4][CH2:5][C:6]([O:8][CH2:9][CH3:10])=[O:7].[P:11]([O:18]CC)([O:15][CH2:16][CH3:17])[O:12][CH2:13][CH3:14]>>[CH2:13]([O:12][P:11]([CH2:2][CH2:3][O:4][CH2:5][C:6]([O:8][CH2:9][CH3:10])=[O:7])([O:15][CH2:16][CH3:17])=[O:18])[CH3:14]Participants
3
Procedure
36.3 g (218 mmol) of ethyl chloroethoxyacetate and 37.4 ml (218 mmol) of triethyl phosphite are heated at 50° C. for 3 hours. The reaction medium is evaporated to dryness under vacuum. 57 g (100%) of crude ethyl (d iethoxyphosphoryl)ethoxyacetate are obtained.
Workup
- customThe reaction medium is evaporated to dryness under vacuum
Sources & evidence
- ORD record
- ord-830901ebf3824f7f9910b2e3512eaff5
- Source dataset
- uspto-grants-2011_09
- Patent number
- US08022079B2
Reaction notes
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