Sodium hydride → HCID 86634732, compound

Participants

Reaction Steps

Using the method of Example 3, Step A, 2-(trifluoromethyl)benzenethiol (1.12 g, 6.31 mmol), 60% sodium hydride in mineral oil (252 mg, 6.31 mmol) and 2-chloro-4-nitropyridine (1.00 g, 12.6 mmol) were reacted to provide 2-chloro-4-(2-(trifluoromethyl)phenylthio)pyridine (1.70 g, 93% yield) as an oil. 1H NMR (CDCl3) δ 8.13 (d, 1H), 7.88 (m, 1H), 7.61-7.72 (m, 4H), 6.85 (s, 1H), 6.80 (m, 1H).

Provenance & Evidence