HRID930075

反应详情

EQUATION

反应方程式

HRID 930075 的结构方程式

PROCEDURE

实验过程

50 mg (0.11 mmol) of the compound of Example 41A is reacted analogously to the synthesis of the compound of Example 1 with 15 mg (0.13 mmol) of 4-imidazolinone-hydrochloride. 47 mg (81% of theory) of the title compound is obtained.