HRID930109

反应详情

EQUATION

反应方程式

HRID 930109 的结构方程式

PROCEDURE

实验过程

109 mg (0.28 mmol) of the compound of Example 65A is reacted analogously to the synthesis of the compound of Example 1 with 38 mg (0.31 mmol) of 4-imidazolinone-hydrochloride. 108 mg (84% of theory) of the title compound is obtained.