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HRID972307

反应详情

EQUATION

反应方程式

HRID 972307 的结构方程式

REACTANTS

反应物

2
结构：O=[N+]([O-])c1cccc(I)c1
HCID12574

1-Iodo-3-nitrobenzene

C6H4INO2

结构：Cc1ccc(=O)[nH]c1
HCID70482

5-Methyl-2-pyridone

C6H7NO

PRODUCTS

生成物

1
结构：Cc1ccc(=O)n(-c2cccc([N+](=O)[O-])c2)c1
HCID9837512

未命名化合物

收率 75%

PROCEDURE

实验过程

The reaction of 24.9 g of 1iodo-3-nitrobenzene (Aldrich Chemical Co.) with 10.9 of 5-methyl-2-(1H)-pyridone by the procedure described in Example 1 affords 16.2g (75%) of 5-methyl-1-(3-nitrophenyl) pyridone.