Iodoethane → HCID 14522775, compound
Reaction equation
[CH2:1]([S:17][CH2:18][CH:19]([CH2:22][O:23][C:24]([C:37]1[CH:42]=[CH:41][CH:40]=[CH:39][CH:38]=1)([C:31]1[CH:36]=[CH:35][CH:34]=[CH:33][CH:32]=1)[C:25]1[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=1)[O:20][CH3:21])[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH3:16].[CH2:43](SCC(COC(C1C=CC=CC=1)(C1C=CC=CC=1)C1C=CC=CC=1)O)CCCCCCCCCCCCCCC.CCI>>[CH2:1]([S:17][CH2:18][CH:19]([CH2:22][O:23][C:24]([C:37]1[CH:38]=[CH:39][CH:40]=[CH:41][CH:42]=1)([C:31]1[CH:32]=[CH:33][CH:34]=[CH:35][CH:36]=1)[C:25]1[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=1)[O:20][CH2:21][CH3:43])[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH3:16]Participants
4
Procedure
This compound was prepared in an analogous manner to that of (±)-1-S-hexadecyl-2-O-methyl-3-O-tritylthioglycerol from 10.0 grams (0.02 mole) of (±)-1-S-hexadecyl-3-O-tritylthioglycerol and 3.3 grams (0.03 mole) of CH3CH2I to provide 10.0 grams of crude product as an oil. 1H-NMR (CDCl3): delta, 0.7-1.7[m, 34H, (CH2)14CH3, CH3 --CH2 --O], 2.3-2.8(m, 4H, CH2 --S--CH2), 3.5-3.9[m, 5H, OCH2 --CH3, CHCH2O], 7.1-7.5 [m, 15H, C(C6H5)3 ].
Sources & evidence
- ORD record
- ord-2d64c4fdd3b5426ebe806504c2f0f8fd
- Source dataset
- uspto-grants-1997_03
- Patent number
- US05614548
Reaction notes
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