HRID990210

反应详情

EQUATION

反应方程式

HRID 990210 的结构方程式

PROCEDURE

实验过程

The operation was carried out in the same manner as in Preparation Example 1 but using 4.07 g (0.02 mols) of a 2-chloro-4,6-diethoxy-1,3,5-triazine and 2.54 g (0.02 mols) of a 3-quinuclidinol to obtain 6.51 g (yield, 98.4%) of white crystals of a 1-(4,6-diethoxy-1,3,5-triazin-2-yl)-3-hydroxyquinuclidinium chloride represented by the following general formula (XII)

WORKUP

后处理

  1. customThe operation was carried out in the same manner as in Preparation Example 1
  2. customto obtain