二氯甲烷 → Didodecyl 2-(thiophen-3-yl)malonate
反应方程式
[S:1]1[CH:5]=[CH:4][C:3]([CH:6]([C:10]([OH:12])=[O:11])[C:7]([OH:9])=[O:8])=[CH:2]1.[CH2:13](O)[CH2:14][CH2:15][CH2:16][CH2:17][CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH2:23][CH3:24].CS(O)(=O)=O.C(Cl)Cl>C1COCC1>[S:1]1[CH:5]=[CH:4][C:3]([CH:6]([C:7]([O:9][CH2:24][CH2:23][CH2:22][CH2:21][CH2:20][CH2:19][CH2:18][CH2:17][CH2:16][CH2:15][CH2:14][CH3:13])=[O:8])[C:10]([O:12][CH2:13][CH2:14][CH2:15][CH2:16][CH2:17][CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH2:23][CH3:24])=[O:11])=[CH:2]1参与物
6
实验过程
In a one-necked flask, 3-thienylmalonic acid (10.0 g, 53.7 mmol) and 1-dodecanol (4 eq., 40.0 g, 215 mmol) were dissolved in THF (80 mL) at room temperature. To this solution was added methanesulphonic acid (1.99 g, 20.7 mmol). The reaction mixture was stirred at room temperature for 3 days. The solvent was then evaporated at 40° C. The residue was re-dissolved in CH2Cl2 to form a solution, which was loaded onto a column (eluent: CH2Cl2) to give didodecyl 2-(thiophen-3-yl)malonate (yield: 18.0 g, 69%). 1H NMR (CDCl3): 0.9 (6H, t), 1.3 (36H, m), 1.7 (4H, m), 4.2 (4H, t), 4.8 (1H, s), 7.2 (1H, d), 7.3 (1H, d), 7.4 (1H, s).
后处理
- customThe solvent was then evaporated at 40° C
- dissolutionThe residue was re-dissolved in CH2Cl2
- customto form a solution, which
来源与证据
- ORD记录
- ord-c14abc847f884fe880e957398e1c90c8
- 来源数据集
- uspto-grants-2014_11
- 专利号
- US08883954B2
反应笔记
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