Potassium Hydroxide → 5-Fluoro-2-biphenylylcyanamide
Reaktionsgleichung
[F:1][C:2]1[CH:3]=[CH:4][C:5]([NH:14][C:15]([NH2:17])=S)=[C:6]([C:8]2[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=2)[CH:7]=1.[OH-].[K+].O.O.O.C([O-])(=O)C.[Pb+2].C([O-])(=O)C>O>[F:1][C:2]1[CH:3]=[CH:4][C:5]([NH:14][C:15]#[N:17])=[C:6]([C:8]2[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=2)[CH:7]=1Komponenten
5
Edukt 3
Produkt 1
Reagenzien, Katalysatoren, Lösungsmittel 1
Versuchsvorschrift
A suspension of N-(5-fluoro-2-biphenylyl)thiourea (8 g) in water (40 ml) was reacted with a solution of potassium hydroxide (18.2 g) in water (40 ml), and a solution of lead acetate trihydrate (12.3 g) in water (70 ml). The reaction mixture heated at 90°-95° C. for 1 hour to give 5-fluoro-2-biphenylylcyanamide as a yellow oil.