Bromine → Perfluorooctyl bromide

HRID 2209863

Reaktionsgleichung

Reaktionsgleichung von HRID 2209863
[F:1][C:2]([F:28])([C:6]([F:27])([F:26])[C:7]([F:25])([F:24])[C:8]([F:23])([F:22])[C:9]([F:21])([F:20])[C:10]([F:19])([F:18])[C:11]([F:17])([F:16])[C:12]([F:15])([F:14])[F:13])C(O)=O.[Br:29]Br.FF>>[F:1][C:2]([Br:29])([F:28])[C:6]([F:27])([F:26])[C:7]([F:25])([F:24])[C:8]([F:23])([F:22])[C:9]([F:21])([F:20])[C:10]([F:19])([F:18])[C:11]([F:17])([F:16])[C:12]([F:15])([F:14])[F:13]

Komponenten

4

Edukt 3

HCID 24408BromineHCID 24524Fluorine2×HCID 67821Perfluorononanoic acid

Produkt 1

HCID 9873Perfluorooctyl bromideAusbeute 142,9 %

Versuchsvorschrift

Perfluorononanoic acid 100 g (0.215 mole), bromine 21.0 g (0.129 mole) and Freon 113 (500 ml) were mixed in the plastic reactor. The mixture was treated with fluorine in the same manner as described in Example 1. Approximately 1.7 fold excess fluorine was used, producing 92 grams of perfluorooctyl bromide (86% yield). Thus, using approximately half the amount of bromine as used in Example 1 produced a lower yield of the perfluoroalkyl halide.

Quellen und Nachweise

ORD-Eintrag
ord-a8f75fceb2184feea80b206f32a1ed69
Quelldatensatz
uspto-grants-1995_10
Patentnummer
US05455373

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