Phenethyl bromide → Ethyl (phenethylthio)acetate
Reaktionsgleichung
CC1C=CC(C[S:7][CH2:8][C:9]([O:11][CH2:12][CH3:13])=[O:10])=CC=1.Br[CH2:17][CH2:18][C:19]1[CH:24]=[CH:23][CH:22]=[CH:21][CH:20]=1.CC[O-].[Na+].SCC(OCC)=O>C(O)C>[CH2:17]([S:7][CH2:8][C:9]([O:11][CH2:12][CH3:13])=[O:10])[CH2:18][C:19]1[CH:24]=[CH:23][CH:22]=[CH:21][CH:20]=1Komponenten
6
