Lithium Hydroxide → 3-(2-Butoxy-4-fluoro-phenyl)-acrylic acid
Reaction equation
C[O:2][C:3](=[O:18])[CH:4]=[CH:5][C:6]1[CH:11]=[CH:10][C:9]([F:12])=[CH:8][C:7]=1[O:13][CH2:14][CH2:15][CH2:16][CH3:17].[Li+].[OH-]>C1COCC1.CO>[CH2:14]([O:13][C:7]1[CH:8]=[C:9]([F:12])[CH:10]=[CH:11][C:6]=1[CH:5]=[CH:4][C:3]([OH:18])=[O:2])[CH2:15][CH2:16][CH3:17]Participants
5
Procedure
3-(2-Butoxy-4-fluoro-phenyl)-acrylic acid methyl ester (121 mg) was reacted with 1N LiOH (5 ml) in THF and CH3OH for 2 hrs as described above to yield title compound (116 mg).
Sources & evidence
- ORD record
- ord-793a11aa25ad47729130e073c0c5d3cd
- Source dataset
- uspto-grants-2013_10
- Patent number
- US08557872B2
Reaction notes
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