Reaction equation
[F:1][C:2]1[C:8]([F:9])=[C:7](Br)[C:6]([F:11])=[C:5]([F:12])[C:3]=1[NH2:4].[CH3:13][O:14][C:15]1[CH:16]=[C:17](B(O)O)[CH:18]=[CH:19][CH:20]=1.C1(P(C2C=CC=CC=2)C2C=CC=CC=2)C=CC=CC=1.C(=O)([O-])[O-].[K+].[K+]>COCCOC>[F:1][C:2]1[C:8]([F:9])=[C:7]([C:19]2[CH:18]=[CH:17][CH:16]=[C:15]([O:14][CH3:13])[CH:20]=2)[C:6]([F:11])=[C:5]([F:12])[C:3]=1[NH2:4]Participants
Conditions
- Temperature
- 90 °C
Procedure
2,3,5,6-Tetrafluoro-4-bromoaniline (7.5 g, 30.7 mmol) is dissolved in DME (150 mL) and treated with 3-methoxyphenylboronic acid (4.7 g, 30.7 mmol), a catalytic amount of tetrakistriphenylphosphine palladium(0) (0.70 g, 0.6 mmol) and triphenylphosphine (0.66 g, 2.5 mmol). Potassium carbonate (8.5 μg in 50 mL of water) is added and the reaction mixture stirred and heated to 90° C. for 24 hours. After cooling to room temperature most of the DME is removed by rotary evaporator under high vacuum. The resulting material is partitioned between EtOAc (200 mL) and water (250 mL). The organic layer is washed with brine, dried (Na2SO4) and concentrated by rotary evaporator. The crude reaction product is purified by flash chromatography (9:1 hexanes/EtOAc, then 6:4 hexanes/EtOAC) to give 2,3,5,6-tetrafluoro-4-(3′-methoxyphenyl)aniline (m.p. 94–96° C.).
Workup
- customis removed by rotary evaporator under high vacuum
- customThe resulting material is partitioned between EtOAc (200 mL) and water (250 mL)
- washThe organic layer is washed with brine
- dry with materialdried (Na2SO4)
- concentrationconcentrated by rotary evaporator
- customThe crude reaction product
- customis purified by flash chromatography (9:1 hexanes/EtOAc
Sources & evidence
- ORD record
- ord-c0a8c1fe4a3c4fe9b0f239282dd887b2
- Source dataset
- uspto-grants-2007_04
- Patent number
- US07202364B2
Linked notes
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