Lithium Hydroxide → 2-Chloro-4-(3-fluoro-4-(thiazol-4-yl)phenylamino)pyrimidine-5-carboxylic acid
Reaction equation
[Cl:1][C:2]1[N:7]=[C:6]([NH:8][C:9]2[CH:14]=[CH:13][C:12]([C:15]3[N:16]=[CH:17][S:18][CH:19]=3)=[C:11]([F:20])[CH:10]=2)[C:5]([C:21]([O:23]CC)=[O:22])=[CH:4][N:3]=1.[Li+].[OH-]>C1COCC1>[Cl:1][C:2]1[N:7]=[C:6]([NH:8][C:9]2[CH:14]=[CH:13][C:12]([C:15]3[N:16]=[CH:17][S:18][CH:19]=3)=[C:11]([F:20])[CH:10]=2)[C:5]([C:21]([OH:23])=[O:22])=[CH:4][N:3]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To a suspension of ethyl 2-chloro-4-(3-fluoro-4-(thiazol-4-yl)phenylamino)pyrimidine-5-carboxylate (186 mg, 0.491 mmol) in THF (4 mL), aq. 1N LiOH (1.00 mL, 1.00 mmol) was added. The suspension became clear with stirring. The mixture was then stirred at room temperature overnight. Upon acidification of the mixture with 1N HCl, white solids precipitated out, which were collected, and dried on vacuum to give 2-chloro-4-(3-fluoro-4-(thiazol-4-yl)phenylamino)pyrimidine-5-carboxylic acid (158 mg). MS 351.2 and 353.3 (M+H, Cl pattern)